Shortest word
Codewars Kata 1 √
Description:
Simple, given a string of words, return the length of the shortest word(s). String will never be empty and you do not need to account for different data types.
My solution:
s = input("Input the words:")
l_split = s.split(' ')
shortest = 100
for word in l_split:
if len(word)<shortest:
shortest = len(word)
print(shortest)
Given solutions:
def find_short(s):
return min(len(x) for x in s.split())
split()
语法：str.split(str=””, num=string.count(str)).
参数：
str – 分隔符，默认为所有的空字符，包括空格、换行(\n)、制表符(\t)等。
num – 分割次数。
def find_short(s):
return min(map(len, s.split(' ')))
map() 语法：map(function, iterable, …)
参数：
function – 函数
iterable – 一个或多个序列
def find_short(s):
return len(min(s.split(' '), key=len))
今日Tips：Markdown换行要在末尾加至少两个空格
