Replace With Alphabet Position
Codewars Kata 14√
Description
Link: alphabet_position
-简述：本题给定一个英文句子的字符串，要求把字母转换成数字，a对应1，b对应2，以此类推。
-思路：遍历每个字母转换为数字。
-难点：无
In this kata you are required to, given a string, replace every letter with its position in the alphabet.
If anything in the text isn’t a letter, ignore it and don’t return it. a being 1, b being 2, etc.
As an example: alphabet_position(“The sunset sets at twelve o’ clock.”)
Should return “20 8 5 19 21 14 19 5 20 19 5 20 19 1 20 20 23 5 12 22 5 15 3 12 15 3 11” as a string.
My solution
def alphabet_position(text):
lst = []
court = 0
txt = text.lower()
for i in range(0,len(text)):
if txt[i].isalpha():
b = ord(txt[i])-96
lst.append(b)
i+=1
else:
i+=1
return ' '.join(str(x) for x in lst)
# 注意返回的形式（如何不以数组形式返回）
Given solutions
def alphabet_position(text):
return ' '.join(str(ord(c) - 96) for c in text.lower() if c.isalpha())
Improved solutions:
def alphabet_position(text):
return ' '.join([str(ord(i)-96) for i in text.lower() if i.isalpha()])
Points
1 ord()函数以一个字符（长度为1的字符串）作为参数，返回对应的 ASCII 数值，或者 Unicode 数值。
2 given solution的表达式是我的答案的列表推导式，很方便，可以多用。
