Extract the domain name from a URL
Codewars Kata 35√
Description
Description: https://www.codewars.com/kata/514a024011ea4fb54200004b
-简述：本题给定一个网址，要求提取其中的网页名部分（即.com之前的部分）
-思路：以不同的分隔符来分割字符串提取
-难点：1 考虑多种网址的情况
Write a function that when given a URL as a string, parses out just the domain name and returns it as a string. For example:
domain_name(“http://github.com/carbonfive/raygun”) == “github” domain_name(“http://www.zombie-bites.com”) == “zombie-bites” domain_name(“https://www.cnet.com”) == “cnet”
My solution
def domain_name(url):
return url.split('//')[-1].split('www.')[-1].split('.')[0]
# 取//后面
# www.后面的关键词
# 以 ' . '分割
Given solution
def domain_name_01(self, url):
url = url.split('/')
return url[0 if len(url) == 1 else 2].split('.')[-2]
def domain_name_02(self, url):
return url.split('//')[-1].split('/')[0].split('.')[-2]
def domain_name_03(self, url):
result = re.search(r"(//)?((?P<domain>\w+)\.)+", url)
return result.group('domain') if result else None
def domain_name_04(self, url):
result = re.search(r"(//)?(\w+\.)?(?P<domain>\w+)\.", url)
return result.group('domain') if result else None
Points
1 串联分割split用法
ps:回头再做这题就觉得超简单了ㄟ( ▔, ▔ )ㄏ
